JEE Main 2025 — Gravitation Question with Solution
From: JEE Main 2025 (Online) 22nd January Morning Shift
Question
A small point of mass is placed at a distance from the centre ' ' of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is . A spherical part of radius is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of is found to be . The value of ratio is

This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Step-by-step explanation

Given mass of whole sphere =
= mass of removed sphere
Due to whole sphere,
(using Newton's gravitational law)
=Force due to whole sphere Force due to removed sphere
So,
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Gravitation chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2025, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.