JEE Main 2015 — Gravitation Question with Solution
From: JEE Main 2015 (Offline)
Question
From a solid sphere of mass and radius a spherical portion of radius is removed, as shown in the figure. Taking gravitational potential at the potential at the center of the cavity thus formed is:
( )
( )
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D
Step-by-step explanation
Before removing the spherical portion, potential at point (Center of cavity)
Mass of removed part = =
Due to cavity part potential at point
=
=
So potential at P due to remaining part,
Note : Potential inside the sphere of radius R and at a distance r from the center,
V =
Here M = mass of the sphere, r = distance from the center of the sphere
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This is a previous-year question from JEE Main 2015, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.