JEE Main 2019PhysicsGravitationKeplers Law And Universal Law Of GravitationmediumMCQ

JEE Main 2019Gravitation Question with Solution

From: JEE Main 2019 (Online) 12th January Morning Slot

Question

A straight rod of length L extends from x = a to x = L + a. The gravitational force it exerts on a point mass 'm' at x = 0, if the mass per unit length of the rod is A + Bx2 , is given by :

Choose an option

Show full solutionCorrect option: B
Correct answer
B

Step-by-step explanation

JEE Main 2019 (Online) 12th January Morning Slot Physics - Gravitation Question 162 English Explanation
dm = (A + Bx2)dx

dF =

F = (A + Bx2)dx

= GM

= GM

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About this question

This is a previous-year question from JEE Main 2019, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.