JEE Main 2022PhysicsCurrent ElectricityEasyMCQ

JEE Main 2022 — Current Electricity Question with Solution

JEE Main 2022 (25 Jun Shift 2)

Question

Two cells of the same EMF E but different internal resistances r1 and r2 are connected in series with an external resistance R as shown in the figure. The terminal potential difference across, the second cell is found to be zero. The external resistance R must then be:

Choose an option

Show full solutionCorrect option: C
Correct answer
Cr2-r1

Step-by-step explanation

In this question we have to find the Terminal potential difference of second cell, we are given the internal resistances of both the cells and an external resistance. Applying the following expression:-

V = E-ir2

⇒0=E-ir2

Applying the expression of current

0=E-2Er1+r2+R·r2

⇒R=r2-r1

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About this question

This is a previous-year question from JEE Main 2022, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.