JEE Main 2024PhysicsCurrent ElectricityEasyMCQ

JEE Main 2024 — Current Electricity Question with Solution

JEE Main 2024 (01 Feb Shift 2)

Question

In an ammeter, 5% of the main current passes through the galvanometer. If resistance of the galvanometer is G, the resistance of ammeter will be:

Choose an option

Show full solutionCorrect option: A
Correct answer
AG20

Step-by-step explanation

As potential drop across both branches would be the same, we get ISS=IgG

95100IS=5I100G

⇒S=G19

Now, resistance of ammeter will be

RA=SGS+G=G21920G19

⇒RA=G20

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About this question

This is a previous-year question from JEE Main 2024, covering the Current Electricity chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.