13 JEE Main 2019 Limits previous-year questions with verified answers and step-by-step solutions.
These are the JEE Main 2019 previous-year questions from the Limits chapter of Mathematics. Each links to a full solution with a verified answer key. To see the whole chapter across all years, visit the Limits chapter hub.
The value of l i m y → 0 1 + 1 + y 4 - 2 y 4
For each x ∈ R , let x be the greatest integer less than or equal to x . Then l i m x → 0 - x x + x sin …
lim x → 1 - π - 2 sin - 1 x 1 - x is equal to
If   l i m x → 1 x 4 - 1 x - 1 = l i m x → k x 3 - k 3 x 2 - k 2 , then k is
If f x = x - x 4 ,   x ∈ R , where x denotes the greatest integer function, then:
l i m x → 0   s i n 2 x 2 - 1 + c o s x equals
l i m x → 0 x + 2 s i n x x 2 + 2   s i n   x + 1   -   s i n 2 x - x + 1 is
l i m x → π 4 c o t 3 x - t a n x c o s x + π 4 is
If lim x → 1 x 2 - a x + b x - 1 = 5 , then a + b is equal to:
Let f : R → R be a differentiable function satisfying f ' 3 + f ' 2 = 0 . Then l i m x → 0 1 + f 3 + x - f…
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