JEE Main 2023MathematicsFunctions

JEE Main 2023 — Functions Questions with Solutions

34 JEE Main 2023 Functions previous-year questions with verified answers and step-by-step solutions.

These are the JEE Main 2023 previous-year questions from the Functions chapter of Mathematics. Each links to a full solution with a verified answer key. To see the whole chapter across all years, visit the Functions chapter hub.

  1. Q12023MCQMedium

    Let f : R → R be a function such that f x = x 2 + 2 x + 1 x 2 + 1 . Then

  2. Q22023MCQMedium

    Let 5 f x + 4 f 1 x = 1 x + 3 ,   x > 0 . Then 18 ∫ 1 2 f x d x is equal to

  3. Q32023MCQMedium

    Let f : ℝ → ℝ be a function defined by f x = log m   2 sin x - cos x + m - 2 , for some m , such…

  4. Q42023MCQMedium

    Let D be the domain of the function f x = sin - 1 log 3 x 6 + 2 log 3 x - 5 x . If the range of the function g : D &#85…

  5. Q52023MCQMedium

    If the domain of the function f x = x 1 + x 2 , where x is greatest integer ≤ x , is [ 2 , 6 ) , then its range is

  6. Q62023MCQMedium

    If f x = 2 2 x 2 2 x + 2 , x ∈ R , then f 1 2023 + f 2 2023 + f 3 2023 . . . . . . . . . f 2022 2023 is equal to

  7. Q72023MCQMedium

    If the domain of the function f x = log e 4 x 2 + 11 x + 6 + sin - 1 4 x + 3 + cos - 1 10 x + 6 3 is ( α ,  …

  8. Q82023MCQEasy

    The range of f x = 4 sin - 1 x 2 x 2 + 1 is

  9. Q92023MCQMedium

    Consider a function f : ℕ → ℝ , satisfying f 1 + 2 f 2 + 3 f 3 + … + x f x = x x + 1 f x  …

  10. Q102023MCQHard

    Let f : R - 2 , 6 → R be real valued function defined as f x = x + 2 x + 1 x 2 - 8 x + 12 . Then range of f is

24 more questions ahead

Log in to unlock the full list, track what you've solved, and practice on the TCS iON-style CBT player. It's free.

Frequently asked questions

How many Functions questions came in JEE Main 2023?
PrepSharp has catalogued 34 JEE Main 2023 Functions questions, each with a verified answer and a step-by-step solution.
Where can I find solutions to JEE Main 2023 Functions questions?
Open any question below to read its full step-by-step solution and verified answer key — free on PrepSharp.