JEE Main 2013 — Thermodynamics (C) Question with Solution
JEE Main 2013 (07 Apr)
Question
A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of . As it does so, it absorbs 208 J of heat. The values of q and w for the process will be
(R = 8.314 J/mol K) (ln7.5 = 2.01)
(R = 8.314 J/mol K) (ln7.5 = 2.01)
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
Since, temperature remains constant, the process will be isothermal by nature.
For Isothermal reversible expansion:
{heat absorbed so +ve}
{expansion so work done is -ve}
For Isothermal reversible expansion:
{heat absorbed so +ve}
{expansion so work done is -ve}
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