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JEE Main 2022 — Thermodynamics (C) Question with Solution

JEE Main 2022 (26 Jun Shift 1)

Question

For complete combustion of methanol

CH3OHl+32O2g→CO2g+2H2Ol the amount of heat produced as measured by bomb calorimeter is 726 kJ mol-1 at 27 °C. The enthalpy of combustion for the reaction is -x kJ mol-1, where x is
integer)
(Given : R=8.3JK-1 mol-1)

Enter your answer

Show full solutionCorrect answer: 727
Correct answer
727

Step-by-step explanation

CH3OHl+32O2g→CO2g+2H2Ol.

For chemical reaction : ΔH=ΔU+ΔngRT

ΔH=-726+-128.314×10-3×300

=-727.245KJ/mole

∴ x=727

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About this question

This is a previous-year question from JEE Main 2022, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.