JEE Main 2024ChemistryThermodynamics (C)MediumNumerical

JEE Main 2024 — Thermodynamics (C) Question with Solution

JEE Main 2024 (31 Jan Shift 2)

Question

If 5 moles of an ideal gas expands from 10L to a volume of 100L at 300K under isothermal and reversible condition then work, w, is −x J. The value of x is -_______.

(Given R=8.314 J K-1 mol-1)

Enter your answer

Show full solutionCorrect answer: -28721
Correct answer
-28721

Step-by-step explanation

Given,

 T=300K,V1=10L,V2=100L,n=5

It is isothermal reversible expansion, so work done negative

W=−2.303nRT logV2V1

=−2.303×5×8.314×300 log10010

=−28720.713J

≡−28721J

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Thermodynamics (C) chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2024, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.