JEE Main 2019ChemistryThermodynamics (C)HardMCQ

JEE Main 2019 — Thermodynamics (C) Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

Enthalpy of sublimation of iodine is 24 cal g-1 at  200°C . If specific heat of I2 (s) and I2 (vap) are 0.055 and 0.031 cal g-1K-1 respectively, then enthalpy of sublimation of iodine at 250°C in cal g-1 is:

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Show full solutionCorrect option: C
Correct answer
C22.8

Step-by-step explanation

I2s→I2g
ΔH250oC-ΔH200oC=ΔCpmT2-T1
ΔH250oC-24=0.013-0.055×50
ΔH250oC-24=-1.2
(ΔH)250oC=22.8 J/gm

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About this question

This is a previous-year question from JEE Main 2019, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.