JEE Main 2014ChemistryThermodynamics (C)MediumMCQ

JEE Main 2014 — Thermodynamics (C) Question with Solution

JEE Main 2014 (06 Apr)

Question

For complete combustion of ethanol,
C 2 H 5 OH l + 3 O 2 g → 2 CO 2 g + 3 H 2 O l ,
the amount of heat produced as measured in bomb calorimeter, is 1364.47 kJ mol -1 at 2 5 ℃ . Assuming ideality the Enthalpy of combustion, Δ c H , for the reaction will be: R = 8.314 kJ mol -1

Choose an option

Show full solutionCorrect option: A
Correct answer
A - 1366.95 kJ mol -1

Step-by-step explanation

Δ n g = Gaseous moles products - Gaseous moles reactants

           = 2 - 3 = -1 mole

Δ H = Δ E + Δ n g RT

        = - 1364.47 - 1 × 8.314 × 1 0 - 3 × 2 9 8 [The value of R must be converted into kJ, so it is multiplied by 10-3]

        = - 1364.47 - 2.49

        = - 1366.96 kJ m -1

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About this question

This is a previous-year question from JEE Main 2014, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.