JEE Main 2023ChemistryThermodynamics (C)HardNumerical

JEE Main 2023Thermodynamics (C) Question with Solution

JEE Main 2023 (01 Feb Shift 2)

Question

0.3 g of ethane undergoes combustion at 27°C in a bomb calorimeter. The temperature of calorimeter system (including the water) is found to rise by 0.5°C. The heat evolved during combustion of ethane at constant pressure is kJmol-1.
(Nearest integer)

[Given : The heat capacity of the calorimeter system is 20 kJ K-1,R=8.3JK-1 mol-1.
Assume ideal gas behaviour.

Assume ideal gas behaviour.

Atomic mass of C and H are 12 and 1 g mol-1 respectively]

Enter your answer

Show full solutionCorrect answer: 1006
Correct answer
1006

Step-by-step explanation

The bomb calorimeter is an instrument used to measure the heat of reaction at a fixed volume and the measured heat which is called the change of internal energy.
By combustion of 1 mole

C2H6(ΔU)=-Heat capacity×Tmass×Molar mass=-20×0.50.3×30=-1000 kJ

C2H6( g)+7/2O2( g)2CO2( g)+3H2O(l)

Δng=2-(2+7/2)=-(7/2)

ΔH=ΔU+ΔnRT

=-1000-7/2×8.3×300 kJ

=-1000-6.225

=-1006 kJ

So heat released =1006 kJ mol-1

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermodynamics (C) chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.