JEE Main 2019ChemistrySurface ChemistryAdsorptioneasyMCQ

JEE Main 2019Surface Chemistry Question with Solution

From: JEE Main 2019 (Online) 8th April Morning Slot

Question

Adsorption of a gas follows freundlich adosorbed isotherm. x is the mass of the gas adsorbed on mass m of the adsorbent. The plot log versus log p is shown in the given graph. is proportional to : JEE Main 2019 (Online) 8th April Morning Slot Chemistry - Surface Chemistry Question 87 English

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Correct answer
Ap2/3

Step-by-step explanation

According to Freundlich adsorption isotherm, in the median range of pressure

       

   = kP

taking log both sides, we get,

log = logk + logP

Here in graph between log and logP, slope is and intercepts = log k.

From the given graph,

slope =

=

   n =

= kP

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About this question

This is a previous-year question from JEE Main 2019, covering the Surface Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.