JEE Main 2020 — Surface Chemistry Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
The mass of gas adsorbed, x, per unit mass of
adsorbate, m, was measured at various pressures,
p. A graph between
and log p gives a
straight line with slope equal to 2 and the intercept
equal to 0.4771. The value of
at a pressure of
4 atm is :
(Given log 3 = 0.4771)
(Given log 3 = 0.4771)
Enter your answer
Show full solutionCorrect answer: 48
Correct answer
48
Step-by-step explanation
According to Freundlich adsorption isotherm, in the median range of pressure
= kP ....(1)
taking log both sides, we get,
log = logk + logP
Here in graph between log and logP, slope is and intercepts = log k.
Given, log k = 0.4771 k = 3
Slope = 2
put in eq. (1), = 3 (4)2 = 48
= kP ....(1)
taking log both sides, we get,
log = logk + logP
Here in graph between log and logP, slope is and intercepts = log k.
Given, log k = 0.4771 k = 3
Slope = 2
put in eq. (1), = 3 (4)2 = 48
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This is a previous-year question from JEE Main 2020, covering the Surface Chemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.