JEE Main 2026 — Solutions Question with Solution

Solution A is prepared by dissolving $1$ g of a protein (molar mass $=50000$ g mol${}^{-1}$) in $0.5$ L of water at $300$ K. Its osmotic pressure is $x$ bar. Solution B is made by dissolving $2$ g of same protein in $1$ L of water at $300$ K. Osmotic pressure of solution B is $y$ bar. Entire solution of A is mixed with entire solution of B at same temperature. The osmotic pressure of resultant solution is $z$ bar. $x,y$ and $z$ respectively are:
$(R=0.083$ L bar mol${}^{-1}$ K${}^{-1})$