JEE Main 2026 — Solutions Question with Solution

For Statement I:
Molarity of the solution in Chamber 1 ($M_1$) = $\frac{18/180}{100/1000}=1$ M
Molarity of the solution in Chamber 2 ($M_2$) = $\frac{30/180}{250/1000}=\frac{1/6}{1/4}=0.667$ M
Since $M_1>M_2$, the solution in Chamber 1 has a higher solute concentration. During osmosis, the solvent (water) moves from the region of lower solute concentration to the region of higher solute concentration across a semi-permeable membrane. Thus, water will move from Chamber 2 to Chamber 1. Statement I is false.

For Statement II:
The osmotic pressure is given by $\pi =iCRT$
For $K_{2}S{O}_4$, assuming complete dissociation ($K_{2}S{O}_4\to 2K^{+}+S{O}_4^{2-}$), the van't Hoff factor $i=3$.
Concentration $C=\frac{50\times 10^{-3}}{174\times 2}$ mol/L
$\pi =3\times \left(\frac{50\times 10^{-3}}{174\times 2}\right)\times 0.083\times 300$
$\pi =\frac{3\times 0.05\times 24.9}{348}=\frac{3.735}{348}\approx 0.0107$ bar
Statement II is true.

Therefore, Statement I is false but Statement II is true.

Answer: Statement I is false but Statement II is true