JEE Main 2022ChemistrySolutionsHardNumerical

JEE Main 2022 — Solutions Question with Solution

JEE Main 2022 (24 Jun Shift 2)

Question

A company dissolves 'x' amount of CO2 at 298 K in 1 litre of water to prepare soda water. X=×10-3 g. (nearest integer)

(Given: partial pressure of CO2 at 298 K=0.835 bar. Henry's law constant for CO2 at 298 K=1.67 kbar. Atomic mass of H,C and O is 1,12, and 6 g mol-1, respectively)

Enter your answer

Show full solutionCorrect answer: 1221
Correct answer
1221

Step-by-step explanation

Using Henry’s law
Pgas = KH .Xgas

10-3X0.835=1.67nCO2nCO2+55.510-3X0.5=nCO2nCO2+55.5nCO255.5=0.5 X10-3nCO2=27.75X10-3WCO2=27.75X10-3X44=1221X10-3g

 

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About this question

This is a previous-year question from JEE Main 2022, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.