JEE Main 2022ChemistrySolutionsEasyNumerical

JEE Main 2022 — Solutions Question with Solution

JEE Main 2022 (27 Jun Shift 1)

Question

2 g of a non-volatile non-electrolyte solute is disolved in 200 g of two different solvents A and B whose ebullioscopic constants are in the ratio of 1:8. The elevation in boiling points of A and B are in the ratio xyx:y. The value of y is____(Nearest Integer)

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Show full solutionCorrect answer: 8
Correct answer
8

Step-by-step explanation

Given : KbAKbB=18

∴ ΔTBAΔTBB=KbA·mKbB·m=18=xy

∵ xy=18

∴ y=8 (nearest integer)

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About this question

This is a previous-year question from JEE Main 2022, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.