JEE Main 2023ChemistrySolutionsEasyNumerical

JEE Main 2023 — Solutions Question with Solution

JEE Main 2023 (31 Jan Shift 1)

Question

The total pressure of a mixture of non-reacting gases X(0.6 g) and Y(0.45 g) in a vessel is 740 mm of Hg. The partial pressure of the gas X is mm of Hg. (Nearest Integer)
(Given : molar mass X=20 and Y=45 g mol-1 )

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Show full solutionCorrect answer: 555
Correct answer
555

Step-by-step explanation

Total pressure (PTotal) = 740 mm of Hg

Number of moles of gas X = 0.620

Number of moles of gas Y = 0.4545

Total number of moles = 0.03 + 0.01 = 0.04 mole

The partial pressure of the gas X = Mole fraction × Total pressure 

X = 0.030.04 × 740 = 555

 

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About this question

This is a previous-year question from JEE Main 2023, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.