JEE Main 2024 — Solutions Question with Solution

Osmotic pressure can be calculated as,

$$$\mathrm{\pi }=\mathrm{CRT}$

π is the osmotic pressure

C is the molar concentration of the solute in the solution

R is the universal gas constant

Here given,

 $$\begin{gathered} {\mathrm{T}}_1=273\mathrm{K} \\ {\mathrm{T}}_2=283\mathrm{K} \end{gathered}$$ 

$$\begin{gathered} {\mathrm{\pi }}_1={\mathrm{CRT}}_1 \\ \text{By putting the values in this equation, we get,} \\ 7\times {10}^5=\mathrm{C}\times \mathrm{R}\times 273 \\ \mathrm{CR}=\frac{7\times {10}^5}{273} \\ {\mathrm{\pi }}_2={\mathrm{CRT}}_2 \\ = \frac{7\times {10}^5}{273}\times 283 \\ =72.56\times {10}^4{\mathrm{Nm}}^{-2 } \end{gathered}$$