JEE Main 2021ChemistrySolutionsEasyNumerical

JEE Main 2021 — Solutions Question with Solution

JEE Main 2021 (25 Jul Shift 1)

Question

CO2 gas is bubbled through water during a soft drink manufacturing process at 298 K. If CO2 exerts a partial pressure of 0.835 bar then x m mol of CO2 would dissolve in 0.9 L of water. The value of x is _______. (Nearest integer)

(Henry's law constant for CO2 at 298 K is 1.67×103 bar)

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Show full solutionCorrect answer: 25
Correct answer
25

Step-by-step explanation

From Henry's law

Pgas=KH·Xgas

0.835=1.67×103×nCO20.9×100018

nCO2=0.025

Millimoles of CO2=0.025×1000=25

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About this question

This is a previous-year question from JEE Main 2021, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.