JEE Main 2023ChemistrySolutionsMediumNumerical

JEE Main 2023 — Solutions Question with Solution

JEE Main 2023 (30 Jan Shift 1)

Question

A solution containing 2 g of a non-volatile solute in 20 g of water boils at 373.52 K. The molecular mass of the solute is _____ gmol-1. (Nearest integer)

Given, water boils at 373 K,Kb for water =0.52K kg mol-1

Enter your answer

Show full solutionCorrect answer: 100
Correct answer
100

Step-by-step explanation

Elevation in boiling point:
⇒ΔTb=373.52-373=0.52

ΔTb=Kb·m

⇒0.52=0.52×2 Molar Mass of Solute ×120×10-3

Molar Mass of solute=100 g/mol

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About this question

This is a previous-year question from JEE Main 2023, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.