JEE Main 2023ChemistrySolutionsMediumNumerical

JEE Main 2023 — Solutions Question with Solution

JEE Main 2023 (10 Apr Shift 2)

Question

An aqueous solution of volume 300 cm3 contains 0.63 g of protein. The osmotic pressure of the solution at 300 K is 1.29 mbar. The molar mass of the protein is gmol-1.

Given : R=0.083 LbarK-1 mol-1

Enter your answer

Show full solutionCorrect answer: 40535
Correct answer
40535

Step-by-step explanation

The osmotic pressure of a non-electrolytic solution can be calculated as follows,

π=CRT

π = osmotic pressure

C = molarity=Number of molesVolume of solution in L

1.29×10-3=0.63(MW)(0.3)×(0.083)×300

MW=0.63×0.083×300(0.3)×1.29×10-3

= 40534.88

≈40535 (Nearest integer)

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About this question

This is a previous-year question from JEE Main 2023, covering the Solutions chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.