JEE Main 2023 — s Block Elements Question with Solution

When calcium chloride reacts with sodium carbonate, a double replacement reaction takes place. The products of this reaction are calcium carbonate and sodium chloride.${\mathrm{CaCl}}_2+{\mathrm{Na}}_2{\mathrm{CO}}_3\to \underset{\left(\mathrm{X}\right)}{{\mathrm{CaCO}}_3}+\underset{\left(\mathrm{Y}\right)}{2\mathrm{NaCl}}$

To Obtain Calcium chloride from Calcium carbonate we need to react calcium carbonate with Hydro chloric acid.

$\underset{\left(\mathrm{X}\right)}{{\mathrm{CaCO}}_3}+\underset{\left(\mathrm{Z}\right)}{2\mathrm{HCl}}\to {\mathrm{CaCl}}_2+{\mathrm{CO}}_2\left(\mathrm{g}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

$\therefore \left(\mathrm{X}\right) {\mathrm{CaCO}}_3$

$\left(\mathrm{Y}\right) \mathrm{NaCl}$

$\left(\mathrm{Z}\right) \mathrm{HCl}$