JEE Main 2023 — s Block Elements Question with Solution

Hydrogen reacts with carbon monoxide in presence of cobalt catalyst to give methanol.

$2{\mathrm{H}}_2\left(\mathrm{g}\right) + \mathrm{CO}\left(\mathrm{g}\right) \stackrel{\text{Cobalt catalyst}}{\to } {\mathrm{CH}}_3\mathrm{OH}\left(\mathrm{l}\right)$

As the mixture of $\mathrm{CO}$ and ${\mathrm{H}}_2$ is used for the synthesis of methanol and a number of hydrocarbons, it is called synthesis gas or syngas. The process of producing syngas from coal is called coal gasification.

$\mathrm{C}\left(\mathrm{s}\right) + {\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right) \stackrel{1270\mathrm{K}}{\to } \mathrm{CO}\left(\mathrm{g}\right) + {\mathrm{H}}_2\left(\mathrm{g}\right)$

The reaction of steam with hydrocarbons or coke at high temperature in presence of nickel catalyst gives a mixture of $\mathrm{CO}$ and ${\mathrm{H}}_2$, called water gas.

${\mathrm{CH}}_4\left(\mathrm{g}\right) + {\mathrm{H}}_2\mathrm{O}\left(\mathrm{g}\right) \underset{\mathrm{Ni}}{\overset{1270\mathrm{K}}{\to }} \mathrm{CO}\left(\mathrm{g}\right) + 3{\mathrm{H}}_2\left(\mathrm{g}\right)$

Electrolysis of brine solution produces ${\mathrm{H}}_2$ gas at cathode and ${\mathrm{Cl}}_2$ gas at anode.

Cathode: $2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+ 2{\mathrm{e}}^{-} \to {\mathrm{H}}_2\left(\mathrm{g}\right) + 2{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)$

Anode: $2{\mathrm{Cl}}^{-} \left(\mathrm{aq}\right) \to {\mathrm{Cl}}_2 \left(\mathrm{g}\right) + 2{\mathrm{e}}^{-}$

The overall reaction is $2{\mathrm{Na}}^{+} \left(\mathrm{aq}\right) + 2{\mathrm{Cl}}^{-} \left(\mathrm{aq}\right) + 2{\mathrm{H}}_2\mathrm{O} \left(\mathrm{l}\right) \to {\mathrm{Cl}}_2 \left(\mathrm{g}\right) + {\mathrm{H}}_2 \left(\mathrm{g}\right) + 2{\mathrm{Na}}^{+} \left(\mathrm{aq}\right) + 2{\mathrm{OH}}^{-} \left(\mathrm{aq}\right)$

So, the correct answer is A-IV, B-III, C-II, D-I