JEE Main 2021 — Hydrogen Question with Solution
From: JEE Main 2021 (Online) 24th February Morning Shift
Question
(A) HOCI + H2O2 → H3O+ + Cl- + O2
(B) I2 + H2O2 + 2OH- → 2I- + 2H2O + O2
Choose the correct option.
(B) I2 + H2O2 + 2OH- → 2I- + 2H2O + O2
Choose the correct option.
Choose an option
Show full solutionCorrect option: D
Correct answer
DH2O2 acts as reducing agent in equations (A) and (B).
Step-by-step explanation
In equation (A), HOCl undergoes reduction in presence of H2O2.
Here, oxidation state of Cl changes from +1 to –1 (i.e. reduces)
H2O2 act as reducing agent I2 reduces to I- in presence of H2O2.
In equation (B),
Here oxidation state of iodine decreases (from 0 to –1)
H2O2 act as reducing agent in both the equations.
Here, oxidation state of Cl changes from +1 to –1 (i.e. reduces)
H2O2 act as reducing agent I2 reduces to I- in presence of H2O2.
In equation (B),
Here oxidation state of iodine decreases (from 0 to –1)
H2O2 act as reducing agent in both the equations.
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This is a previous-year question from JEE Main 2021, covering the Hydrogen chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.