JEE Main 2023 — Hydrogen Question with Solution
From: JEE Main 2023 (Online) 11th April Morning Shift
Question
Given below are two statements:
Statement-I : Methane and steam passed over a heated catalyst produces hydrogen gas.
Statement-II : Sodium nitrite reacts with to give and .
In the light of the above statements, choose the most appropriate answer from the options given below :
Choose an option
Show full solutionCorrect option: C
Step-by-step explanation
Let's consider each statement:
Statement-I : Methane (CH₄) and steam (H₂O) can indeed react in the presence of a heated nickel catalyst to produce carbon monoxide (CO) and hydrogen gas (H₂). This is known as the steam reforming or steam methane reforming reaction and is industrially significant for hydrogen production. Hence, Statement-I is correct.
Statement-II : Sodium nitrite (NaNO₂) reacts with ammonium chloride (NH₄Cl) to produce nitrogen gas (N₂), water (H₂O), and sodium chloride (NaCl). This is a standard reaction that is often used in inorganic chemistry to produce nitrogen gas. Hence, Statement-II is also correct.
Therefore, the correct answer is Option C: Both the statements I and II are correct.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Hydrogen chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2023, covering the Hydrogen chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.