JEE Main 2015ChemistryElectrochemistryMediumMCQ

JEE Main 2015 — Electrochemistry Question with Solution

JEE Main 2015 (04 Apr)

Question

Two Faraday of electricity is passed through a solution of CuSO4 . The mass of copper deposited at the cathode is: (Atomic mass of Cu = 63.5 amu)

Choose an option

Show full solutionCorrect option: C
Correct answer
C63.5 g

Step-by-step explanation

Cu+2 + 2e- → Cu

2 Faraday charge deposits 1 mol of Cu, or

2 F≡2 Equivalents of Cu

Mass of Cu deposited=2×63.52=63.5g

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About this question

This is a previous-year question from JEE Main 2015, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.