JEE Main 2016ChemistryElectrochemistryMediumMCQ

JEE Main 2016 — Electrochemistry Question with Solution

JEE Main 2016 (10 Apr Online)

Question

Oxidation of succinate ion produces ethylene and carbon dioxide gases. On passing 0.2 Faraday electricity through an aqueous solution of potassium succinate, what is the total volume of gases (at both cathode and anode) at STP (1 atm and 273 K)?

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Show full solutionCorrect option: A
Correct answer
A8.96 L

Step-by-step explanation



Ethene, CO2, H2 are gases.

So total moles of gas =1+2+1=4

By 2 Farady=4 mole of gas produced

So, by 0.2 Farady =0.4 mole gas produced

ν=nRTP=0.4×0.0821×2731=8.96 L

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About this question

This is a previous-year question from JEE Main 2016, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.