JEE Main 2019ChemistryElectrochemistryHardMCQ

JEE Main 2019 — Electrochemistry Question with Solution

JEE Main 2019 (10 Jan Shift 2)

Question

In the cell, PtsH2g, 1bar HCl aqAgClsAgsPts,the cell potential is 0.92 V when a 10-6 molar HCl solution is used. The standard electrode potential of Ag|AgCl|Cl- electrode is:

(Given, 2.303RTF=0.06 V at 298 K)

Choose an option

Show full solutionCorrect option: B
Correct answer
B0.20 V

Step-by-step explanation

A:12H2g→H+ aq.+e-; Eo=0.0 V
C :AgCl s+e-→Ag s+Cl-; Eo=xV
Ecell=Ecello-0.061log⁡H+Cl-
0.92=x-0.061log⁡10-12
0.92=x+0.72
x=0.92-0.72
=0.2V

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About this question

This is a previous-year question from JEE Main 2019, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.