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JEE Main 2022 — Electrochemistry Question with Solution

JEE Main 2022 (28 Jun Shift 2)

Question

For the given reactions

Sn2++2e-→Sn

Sn4++4e-→Sn the electrode potentials are ; ESn2+/Sn°=-0.140 V and ESn4+/Sn°=0.010 V. The magnitude of standard electrode potential for Sn4+/Sn2+ i.e. ESn4+/Sn2+° is____×10-2 V(Nearest integer)

Enter your answer

Show full solutionCorrect answer: 16
Correct answer
16

Step-by-step explanation

(i) Sn2++2e-⟶Sn         E10=-0.14 V

ΔG10=-2 F-0.14

(ii) Sn4++4e-⟶Sn       E20=+0.010 VΔG20=-4F+0.010

Target Sn4++2e-⟶Sn2+      E30=?

ΔG30=-2 FE30

Target Eq.=Eq. ii - Eq. i

-2FE30=-4F0.010--2F-0.14

E30=4×0.010+2×0.142=0.16 V=16×10-2 V

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About this question

This is a previous-year question from JEE Main 2022, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.