JEE Main 2022ChemistryElectrochemistryHardNumerical

JEE Main 2022 — Electrochemistry Question with Solution

JEE Main 2022 (24 Jun Shift 1)

Question

The cell potential for the following cell PtH2gH+aq||Cu2+0.01MCus is 0.576 V at 298 K. The pH of the solution is (Nearest integer)

(Given : ECu2+/Cuo=0.34 V and 2.303RTF=0.06 V)

Enter your answer

Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Anode ⇒H2g⟶2H+aq+2e-

Cathode ⇒Cu2+aq+2e-⟶Cus

Overall ⇒H2q+Cu2+aq⟶2H+aq+Cus¯

Ecell°=ECu2+Cu°-EH+H2°=0.34 V

Ecell=Ecell°-0.062logH+2Cu2+

0.576=0.34+0.03-logH+2+logCu2+

0.576=0.34+0.032pH+logCu2+

0.236=0.032pH-2

7.866=2pH-2

pH=4.93≈5

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Electrochemistry chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Electrochemistry chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.