JEE Main 2024 — D And F Block Elements Question with Solution

The number of unpaired electrons in a transition metal is determined by its electronic configuration in the context of its ground state. The elements listed, Scandium (Sc), Chromium (Cr), Vanadium (V), Titanium (Ti), and Manganese (Mn), are transition metals that have different numbers of unpaired electrons. Here is the electronic configuration and the corresponding number of unpaired electrons for each:

Scandium (Sc):

Electronic Configuration: $$[\mathrm{Ar}]3d^{1}4s^2$$

Unpaired Electrons: 1

Titanium (Ti):

Electronic Configuration: $$[\mathrm{Ar}]3d^{2}4s^2$$

Unpaired Electrons: 2

Vanadium (V):

Electronic Configuration: $$[\mathrm{Ar}]3d^{3}4s^2$$

Unpaired Electrons: 3

Chromium (Cr):

Electronic Configuration: $$[\mathrm{Ar}]3d^{5}4s^1$$

Unpaired Electrons: 6

Manganese (Mn):

Electronic Configuration: $$[\mathrm{Ar}]3d^{5}4s^2$$

Unpaired Electrons: 5

Arranging them in increasing order of number of unpaired electrons:

$$(\mathrm{A})<(\mathrm{D})<(\mathrm{C})<(\mathrm{E})<(\mathrm{B})$$

Therefore, the correct choice is Option B.