JEE Main 2025 — D And F Block Elements Question with Solution

The preparation of potassium permanganate (${\mathrm{KMnO}}_4$) from manganese dioxide (${\mathrm{MnO}}_2$) involves a two-step process. In the first step, ${\mathrm{MnO}}_2$ reacts with potassium hydroxide ($\mathrm{KOH}$) and potassium nitrate (${\mathrm{KNO}}_3$) under heating. This reaction produces potassium manganate (${\mathrm{K}}_2{\mathrm{MnO}}_4$) as an intermediate product. The reaction can be depicted as follows:

${\mathrm{MnO}}_2\underset{{\mathrm{KNO}}_3,\mathrm{\Delta }}{\overset{\mathrm{KOH}}{\to }}{\mathrm{K}}_2{\mathrm{MnO}}_4$