JEE Main 2024 — Alcohols Phenols and Ethers Question with Solution
JEE Main 2024 (27 Jan Shift 1)
Question
Given below are two statements :
Statement (I) : p-nitrophenol is more acidic than m-nitrophenol and o-nitrophenol.
Statement (II) : Ethanol will give immediate turbidity with Lucas reagent.
In the light of the above statements, choose the correct answer from the options given below :
Choose an option
Show full solutionCorrect option: A
Step-by-step explanation
p-Nitrophenol is more acidic than m-nitrophenol and o-nitrophenol.
The electron withdrawing group stabilizes phenoxide ion through effect at para and ortho
position.
group in meta position will show effect.
Presence of group at ortho position it form hydrogen bonding with group. Hence, acidity is less than p-nitrophenol order of acidic strength.
Acidic strength

Ethanol give lucas test after long time
Lucas reagent helps in the distinction of primary, secondary and tertiary alcohols. A small quantity of unknown alcohol is added to Lucas reagent (anhyd. ) at room temperature and the mixture is shaken. A tertiary alcohol forms turbidity immediately, secondary alcohol forms turbidity within five minutes and primary alcohol shows no turbidity at room temperature.

So, Statement I is correct, but Statement II is incorrect.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Alcohols Phenols and Ethers chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2024, covering the Alcohols Phenols and Ethers chapter of Chemistry. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.