JEE Main 2019PhysicsWork Power EnergyHardMCQ

JEE Main 2019Work Power Energy Question with Solution

JEE Main 2019 (09 Apr Shift 2)

Question

A wedge of mass M=4m lies on a frictionless plane. A particle of mass m approaches the wedge with speed v. There is no friction between the particle and the plane or between the particle and the wedge. The maximum height climbed by the particle on the wedge is given by:

Choose an option

Show full solutionCorrect option: C
Correct answer
C2v25g

Step-by-step explanation

From conservation of linear momentum,

mv=4m+mvf
vf=v5
From conservation of mechanical energy,
12mv2=124m+mvf2+mgh
v2=5vf2+2gh
v2=5×v52+2gh
h=2v25g

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Work Power Energy chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2019, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.