JEE Main 2016PhysicsWork Power EnergyMediumMCQ

JEE Main 2016Work Power Energy Question with Solution

JEE Main 2016 (10 Apr Online)

Question

A particle of mass M is moving in a circle of fixed radius R in such a way that its centripetal acceleration at time t is given by n2Rt2, where n is a constant. The power delivered to the particle by the force acting on it, is :

Choose an option

Show full solutionCorrect option: B
Correct answer
BMn2R2t

Step-by-step explanation

ac=v2R=n2Rt2

v=nRT

at=dvdt=nR

Power =Matv

=M nR nRt

=Mn2R2t

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About this question

This is a previous-year question from JEE Main 2016, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.