JEE Main 2024 — Work Power Energy Question with Solution
JEE Main 2024 (04 Apr Shift 1)
Question
If a rubber ball falls from a height and rebounds upto the height of . The percentage loss of total energy of the initial system as well as velocity ball before it strikes the ground, respectively, are :
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Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
$\begin{aligned}
& \text { Velocity just before collision }=\sqrt{2 \mathrm{gh}} \\
& \text { Velocity just after collision }=\sqrt{2 \mathrm{~g}\left(\frac{\mathrm{h}}{2}\right)} \\
& \therefore \Delta \mathrm{KE}=\frac{1}{2} \mathrm{~m}(2 \mathrm{gh})-\frac{1}{2} \mathrm{mgh} \\
& =\frac{1}{2} \mathrm{mgh} \\
& \therefore \% \text { loss in energy } \\
& =\frac{\Delta \mathrm{KE}}{\mathrm{KE}_{\mathrm{i}}} \times 100=\frac{\frac{1}{2} \mathrm{mgh}}{\frac{1}{2} \mathrm{mg} 2 \mathrm{~h}} \times 100=50 \%
\end{aligned}$
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This is a previous-year question from JEE Main 2024, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.