JEE Main 2024PhysicsWork Power EnergyEasyMCQ

JEE Main 2024 — Work Power Energy Question with Solution

JEE Main 2024 (30 Jan Shift 2)

Question

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 60° by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : g=10 m s-2

Choose an option

Show full solutionCorrect option: B
Correct answer
B5 J

Step-by-step explanation

Work done against frictional force  

=μN×10=μmgcos60°×10

=0.1×5×10=5 J

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About this question

This is a previous-year question from JEE Main 2024, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.