JEE Main 2016PhysicsWork Power EnergyEasyMCQ

JEE Main 2016 — Work Power Energy Question with Solution

JEE Main 2016 (10 Apr Online)

Question

The velocity-time graph of a particle of mass 10 kg is shown in the figure. The net work done on the particle in the first two seconds of the motion is

Choose an option

Show full solutionCorrect option: C
Correct answer
C-4500 J

Step-by-step explanation

v=-5t+50

vt=2=40


Work done=∆ K.E. =12402-502×10

=-4500 J

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About this question

This is a previous-year question from JEE Main 2016, covering the Work Power Energy chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.