JEE Main 2017PhysicsWaves and SoundHardMCQ

JEE Main 2017Waves and Sound Question with Solution

JEE Main 2017 (08 Apr Online)

Question

Two wires W1 and W2 have the same radius r and respective, densities ρ1 and ρ2, such that ρ2=4ρ1 . They are joined together at the point O, as shown in the figure. The combination is used as a sonometer wire and kept under tension T. The point O is midway between the two bridges. When a stationary wave is set up in the composite wire, the joint is found to be a node. The ratio of the number of antinodes formed in W1 to W2 is 

Choose an option

Show full solutionCorrect option: B
Correct answer
B1:2

Step-by-step explanation

Let p1 and p2 be the number of antinodes of both wires.

Fundamental frequency remains the same for both wires. 

n1=n2

Tsame

rsame

lsame

n=p2l Tπr2ρ

From the above equation, we have 
p1ρ1  =p2ρ2  

p1p2= ρ1ρ2

The ratio of antinodes is p1p2=12

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About this question

This is a previous-year question from JEE Main 2017, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.