JEE Main 2002 — Waves and Sound Question with Solution
JEE Main 2002
Question
A tuning fork arrangement (pair) produces 4 beats / sec with one fork of frequency . A little wax is placed on the unknown fork and it then produces 2 beats /sec. The frequency of the unknown fork is
Choose an option
Show full solutionCorrect option: B
Correct answer
B292 cps
Step-by-step explanation
The fact that placing wax decreases the frequency of the unknown fork and also the beat frequency states that the unknown fork is of higher frequency.
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Waves and Sound chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2002, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.