JEE Main 2023PhysicsWaves and SoundEasyNumerical

JEE Main 2023 — Waves and Sound Question with Solution

JEE Main 2023 (11 Apr Shift 1)

Question

The equation of wave is given by Y=10-2sin2π160t-0.5x+π4, where x and Y are in m and t in s. The speed of the wave is _______ km h-1.

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Show full solutionCorrect answer: 1152
Correct answer
1152

Step-by-step explanation

The equation of the wave is 

Y=10-2sin2π(160t-0.5x+π4)

The velocity of a wave is given by v=ωk   ...(i).

A wave equation is given by 

Y=Asinωt-kx+ϕ

Using equation (i),

v=2π×1602π×0.5=320 m s-1

⇒v=320×185

⇒v=1152 km h-1

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About this question

This is a previous-year question from JEE Main 2023, covering the Waves and Sound chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.