JEE Main 2025PhysicsWave OpticsHuygens Principle And Interference Of LighteasyNumerical

JEE Main 2025Wave Optics Question with Solution

From: JEE Main 2025 (Online) 28th January Morning Shift

Question

A double slit interference experiment performed with a light of wavelength 600 nm forms an interference fringe pattern on a screen with 10 th bright fringe having its centre at a distance of 10 mm from the central maximum. Distance of the centre of the same 10 th bright fringe from the central maximum when the source of light is replaced by another source of wavelength 660 nm would be ________ mm .

Enter your answer

Show full solutionCorrect answer: 11
Correct answer
11

Step-by-step explanation

In Young's double slit experiment, the distance of maxima from central maxima is given by,

Here, & are same for both the cases.

So,

.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Wave Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2025, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.