JEE Main 2014PhysicsWave OpticsEasyMCQ

JEE Main 2014 — Wave Optics Question with Solution

JEE Main 2014 (19 Apr Online)

Question

In Young’s double-slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single-slit diffraction pattern is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D12

Step-by-step explanation

d = separation between 2 slits

a = slit width

β y = fringe width in YDSE &  β D = width of central maxima

βy=λDd=λD6.1aβD=2λDa

β D =2×6.1  β y

=12.2  β y

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About this question

This is a previous-year question from JEE Main 2014, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.