JEE Main 2012PhysicsWave OpticsMediumMCQ

JEE Main 2012Wave Optics Question with Solution

JEE Main 2012 (12 May Online)

Question

The maximum number of possible interference maxima for slit separation equal to , where is the wavelength of light used, in a Young's double slit experiment is

Choose an option

Show full solutionCorrect option: B
Correct answer
B3

Step-by-step explanation

As and cannot be or Hence maximum number of possible interference maximas, i.e. 3

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About this question

This is a previous-year question from JEE Main 2012, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.