JEE Main 2022PhysicsWave OpticsMediumNumerical

JEE Main 2022 — Wave Optics Question with Solution

JEE Main 2022 (28 Jun Shift 2)

Question

In a Young's double slit experiment, an angular width of the fringe is 0.35° on a screen placed at 2 m away for particular wavelength of 450 nm. The angular width of the fringe, when whole system is immersed in a medium of refractive index 75, is 1α. The value of α is _____ .

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Show full solutionCorrect answer: 4
Correct answer
4

Step-by-step explanation

Angular fringe width is given by θ=λD, where, D is the distance between the source and the screen and λ is the wavelength of the light.

We have, θ1θ2=λ1λ2

Then, θ2=0.35∘450 nm×450 nm75=0.25∘=14   ∵λ2=λ1μ

Thus, value of α=4.

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About this question

This is a previous-year question from JEE Main 2022, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.