JEE Main 2020PhysicsWave OpticsEasyMCQ

JEE Main 2020 — Wave Optics Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

In a double – slit experiment, at a certain point on the screen the path difference between the two interfering waves is 18th of a wavelength. The ratio of the intensity of light at that point to that at the center of a bright fringe is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A0.853

Step-by-step explanation

I=I0cos2∆ϕ2
II0=cos22πλ×∆X2=cos2π8;II0=0.853

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Wave Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Wave Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.