JEE Main 2024PhysicsUnits and DimensionsEasyMCQ

JEE Main 2024 — Units and Dimensions Question with Solution

JEE Main 2024 (30 Jan Shift 2)

Question

If mass is written as m=kcPG-1/2 h1/2, then the value of P will be : (Constants have their usual meaning with k a dimensionless constant)

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Show full solutionCorrect option: A
Correct answer
A12

Step-by-step explanation

Given:

m=kcPG-1/2 h1/2

Writing dimensions on both sides, we get

M1 L0 T0=LT-1PM-1 L3 T-2-1/2ML2 T-11/2

By comparing exponent of L on both the sides, we get

0=P-32+1⇒P=12

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About this question

This is a previous-year question from JEE Main 2024, covering the Units and Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.